A buffer solution was formed by mixing 20.0 cm^3 of sodium hydroxide solution of concentration 0.100 mol dm^–3 with 25.0 cm^3 of ethanoic acid of concentration 0.150 mol dm^–3. CH3COOH + NaOH---CH3COONa + H2O Calculate the pH of this buffer solution.

Ka for ethanoic acid = 1.74 × 10–5 mol dm–3 also given in question. moles = concentration x volume / 1000Ka = [H+] [A-]/[HA]pH = -log [H+]
initial moles:NaOH: 20x0.1/1000 = 0.002molCH3COOH: 25 x 0.15 / 1000 = 0.00375
NaOH< CH3COOH and react in 1:1 ratio, so all NaOH reacts.
final moles:CH3COO- Na+ = initial moles NaOH = 0.002molCH3COOH = 0.00375 - 0.002 = 0.00175
final concentrations (remember to use total volume of 45 cm3)[CH3COO- Na+] = 1000 x 0.002 / 45 = 0.04444 moldm-3 = [A-][CH3COOH] = 1000 x 0.00175 /45 = 0.03889 moldm-3 = [HA]from Ka:[H+] = Ka [HA] / [A-] = 1.74 x 10 -5 x 0.03889 / 0.04444 = 1.523 x 10 -5pH = -log [H+] = 4.82


Related Chemistry A Level answers

All answers ▸

What is a dative covalent bond?


How do I tackle Kc questions?


A compound, HOCH2CH2CH2CH2COCl, reacts with itself to give a new compound. Give the IUPAC name for the starting compound, draw the mechanism for the formation of the new compound and give the prominant feature of the IR spectrum of the new compound.


Sodium chloride and sodium metal can both conduct electricity under differing conditions. Give the conditions required for each to conduct electricity and explain how each conducts electricity.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences