Answers>Maths>IB>Article

Differentiate y = e^(x^2 - 3x).

This question is an example of the chain rule for differentiating. 

Firstly, identify the inner function. In this case, it is x- 3x. This function must be differentiated first:

d/dx (x2 - 3x) = 2x - 3

Secondly, identify the outer function. In this case, it is ez, where z = x2 - 3x. This function must be differentiated second:

d/dz (ez) = e 

The final differentiated result is the derivative of the inner function multiplied by the derivative of the outer function:

dy/dx = (2x - 3)e= (2x - 3)ex^2 - 3x

Answered by Ellie S. Maths tutor

10945 Views

See similar Maths IB tutors

Related Maths IB answers

All answers ▸

dy/dx = 10exp(2x) - 4; when x = 0, y = 6. Find the value of y when x = 2.


Prove that (sinx)^2 + (cosx)^2 = 1


Integrate x^3 * lnx


The normal to the curve x*(e^-y) + e^y = 1 + x, at the point (c,lnc), has a y-intercept c^2 + 1. Determine the value of c.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences