Write 2x^2 - 16x + 6 in the form a(x + b)^2 + c where a, b and c are constants to be determined.

2x^2 - 16x + 6= 2(x^2 - 8x) + 6= 2((x-4)^2 - 16) + 6= 2(x - 4)^2 - 26So a = 2, b = -4 and c = -26

HA

Related Maths GCSE answers

All answers ▸

Work out 2^3 + 4^2


how do you solve these simultaneous equations?


How do I solve simultaneous equations? eg 1) 4x = 16 - 2y and 2) 3x + y = 9


How to I factorise a quadratic equation?