Write 2x^2 - 16x + 6 in the form a(x + b)^2 + c where a, b and c are constants to be determined.
2x^2 - 16x + 6= 2(x^2 - 8x) + 6= 2((x-4)^2 - 16) + 6= 2(x - 4)^2 - 26So a = 2, b = -4 and c = -26
HA
Related Maths GCSE answers
All answers ▸There are N counters in a bag, 4 being red and the rest being blue. I take two counters at random from the bag (without replacing the first).The chance i take two blue counters is 1/3, See below in the answer box
Solve the two equations: Equation 1: 2a - 5b = 11 Equation 2: 3a + 2b = 7
Question: What proportion of the clock is the area covered when the time is 12:10? (Here the question should indicate the time stated and shade in the proportion of the clock to be computed.)
Expand 5(2x-6)