f(x) = x^3+2x^2-x-2 . Solve for f(x) = 0
f(x) = x3 + 2x2 - x - 2 Use the factor theorem to test for f(1) = 0 f(1) = 13 + 2*12 - 1 - 2 = 0 Therefore x = 1 is a solution and (x-1) is a factor of f(x) Now factorise f(x) x3 + 2x2 - x - 2 = (x-1)(x2 + 3x + 2) = (x-1)(x+2)(x+1) So x = 1, -2, -1.
