Why are transition metal complexes coloured?

By definition, all transition metal ions have d orbitals. These are normally degenerate, lying at the same energy level as there is nothing to break the symmetry.

However, in the presence of ligands, the symmetry is broken and the orbitals split into different energy levels. This is due to differing alignment with the ligands resulting in a different electric repulsion from then lone pairs on the ligands.

For example, in an octohedral complex like [Cu(H2O)6]2+, the dx2-y2 and dz2 orbitals point directly at the ligands whereas the dxy, dxz and dyz orbitals all lie between the ligands. This means that the former experience greater electronic repulsion and are therefore raised in energy compared to the latter.

The split in energy levels means that electrons can be excited from the lower to the higher energy level by absorbing a photon. The energy of the this photon relates to its frequency by E=hf meaning that complexes absorb light of one partiular colour. They therefore transmit the complimentary colour and this happens to be in the visible light range so they appear coloured.

ZT
Answered by Zac T. Chemistry tutor

7662 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

Explain why the second ionisation energy of boron is higher than the first ionisation energy of boron?


An amino acid contains 52.2% carbon, 9.3% hydrogen, 8.7% nitrogen and 29.8% oxygen by mass and has a relative molecular mass of 161 g/mol. What is its molecular formula? What functional groups must it have?


Explain the polarity of both CH3CH2Br and CBr3CBr3.


Explain why the first ionisation energy of Strontium is less than the first ionisation energy of Calcium


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning