What is the change in temperature of 2kg of water heated by a kettle using a voltage of 230V at 0.5A of current for 10 seconds? Assume no heat losses.

specific heat capacity of water, c = 4200J/kgK
First student should understand that due to no heat losses the energy provided by mains socket to kettle is the same energy as the heat which changes the water temperature. Q = mcdT = E = P x t
First electrical energy is calculated:E = P * t = I * V * tE = 230 * 0.5 * 10E = 1150 J
Application of energy conservation:E = Q = 1150JQ = mcdT This needs to be rearranged so that dT is the subject. dT = Q/(mc)Therefore our value for the temperature change is :dT = 1150/(24200)dT = 0.136K Which is as expected due to the kettle only being heated for 10 seconds!

WS
Answered by Will S. Physics tutor

1533 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

Find current and voltage across resistors R1 and R2, when they connected in parallel and in series. A 12V battery is connected, R1=4Ω and R2=3Ω.


How do I derive Kepler's 3rd law using Newton's Law of gravitation, in the case of a circular orbit?


Explain the wave - particle duality


If photons are little particles emitted by atoms, where were they before they got emitted?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences