The initial velocity, u, is 50 ms-1 The final velocity, v, is 60 ms-1 The acceleration, a, is 0.5ms-2 The question is asking us to find the time, t. The equation of motion linking u, v, a, and t is v = u + at First we must rearrange the equation to make t the subject: t = (v-u)/a then we can substitute in the values. t = (60-50)/0.5 = 20s Now to find the displacement, s, during this time we can use s = ut + 0.5at2 s = 5020 + 0.50.5*202 = 1,100m = 1.1km