A block of mass m is released from rest on a surface inclined at 30⁰ to the horizontal with a coefficient of friction of 0.3. How long does it take for the block to slide 1 m?
Firstly, a free-body diagram of the problem should be drawn indicating the forces acting on the block (remember that the friction force is the product of the normal reaction on the block and the coefficient of friction). Next, the resultant force acting on the block parallel to the slope should be found and substituted into the equation F = ma: m.g.sin(30) - 0.3.m.g.cos(30) = ma a = 2.356 ms-2 Now the time to travel 1 m can be calculated using SUVAT (or integration and applying boundary conditions). s = ut +0.5at2 1 = 0 + 1.178t2 t = 0.921 s (3dp) //
