Given x^3 + 4x^2 + x - 6 = 0 , and one of the factors of this equation is (x-1), factorise and hence compute the other solutions for the eqaution.
Using either polynomial long division or by inspection, the equation can be reduced to:(x-1)(x2+5x+6)
The other bracket can the be factored out using inspection or the quadratic formula to give:(x-1)(x+2)(x+3)
Therefore, the remaining solutions to the equation are given as:x = -2 or x = -3
