A is the point with coordinates (5, 9) B is the point with coordinates (d, 15) The gradient of the line AB is 3 Work out the value of d.

A straight line equation is defined as y=mx+c where m is the gradient and c is the intercept. Since the gradient is already said to be 3 we can substitute this in to mean the equation for AB is y=3x+c. Since we know point A we can substitute the values for x and y in to solve for c.9=3(5)+c9=15+cc= -6y=3x-6Now we have the equation of the line we can sub in point B to find what d is.15=3(d)-621=3dd=7

Answered by Tarun A. Maths tutor

8983 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Find an equation of the line which passes through the point (4,-7) and has slope 3.


Given: h=3t^2, work out the value of h when t=5.


Solve the following inequality: x^2 + x -12<0


Solve the following simultaneous equations: 2a-5b=11, 3a+2b=7


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences