Find the gradient, length and midpoint of the line between (0,0) and (8,8).

let x1 = 0, y1 = 0 in (0,0) and let x2 = 8 and y2 = 8 in (8,8). To find the gradient, we would do (y2 - y1)/(x2-x1) = 1. To find the length, we would do the square root of the following: (y2-y1)^2 + (y2-y1)^2 which gives us the square root of 128 and this simplifies to 8sqrt(2). For the midpoint, we would do ((x1+x2)/2,(y1+y2)/2) which gives (4,4).The reason why I have opted to use x1, x2, y1 and y2 is to generalise it for any numbers we are given.

JA
Answered by Jason A. Maths tutor

6486 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

A cannonball is fired at an angle of 30 degrees and a velocity of 16 m/s. How long does it take (to 2 significant figures) for the cannonball to reach the ground?


how do you differentiate tan(x)


Evaluate f'(1) for the function f(x) = (x^2 + 2)^5


A curve C is mapped by the equation ( 1+x)(4-x). The curve intersects the x-axis at x = –1 and x = 4. A region R is bounded by C and the x-axis. Use calculus to find the exact area of R.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning