Solve n^2 – n – 90 = 0 to find value of n

Firstly you want to factorise this expression. You have n2, so you know you want to multiple n by itself. Next, you want to think carefully about what two numbers add to get -1 (the coefficient of the second value of the expression, -n) and multiply to get -90. You have two negatives so you know one of your numbers is going to be negative and the other positive (if they were both negative you'd get +90, same if they were both positive). You'll figure out the two numbers you're looking for are - 10 and + 9 ( - 10 + 9 = -1, - 10 x 9 = - 90). So now you have(n + 9)(n - 10) = 0 For this to be true, one of the expressions on the left have to equal 0, so either n + 9 = 0 or n - 10 = 0. The possible values are therefore n = 10 or n = - 9, final answer

Answered by Ahmed I. Maths tutor

3474 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Hannah's sweet problem (Edexcel 2015): There are n sweets, 6 are orange, rest of the sweets are yellow. She takes 2 sweets randomly without replacing them and the probability that 2 orange sweets are chosen is 1/3. Show that n^2-n-90 = 0.


Trigonometry: what is it, and how do I do it?


(x+3)(x-4)(x+5) is identical to x^3 +ax^2 -17x+b. Find the value of a and the value of b.


Find the exact value of the gradient of the curve y=e^(2-x)ln(3x-2) at the point on the curve where x=2.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences