The velocity of a car at time, ts^-1, during the first 20 s of its journey, is given by v = kt + 0.03t^2, where k is a constant. When t = 20 the acceleration of the car is 1.3ms^-2, what is the value of k?

Our task is to find out the value of k, which we can determine from the equations for velocity or acceleration if we know 2 of the 3 variables in either equation. We are given the value of acceleration at t(20)=1.3ms^-1, so we should substitute these values into the equation for acceleration, which we can calculate by differentiating the velocity: a = k + 0.06t. This gives us 1.3 = k + 0.06(20) -> 1.3 = k + 1.2 -> 0.1 = k.

LM
Answered by Lascelle M. Maths tutor

7863 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

If a 5 metre ladder is resting against a wall and the bottom of the ladder is 3 metres away from the wall, and someone pulls the bottom of the ladder away at a speed of 1 metre per second, calculate the speed of the top of the ladder after t seconds


Find the area bounded be the curve with the equation y = x^2, the line x = 1, the line x = -1, and the x-axis.


What is the velocity of the line from vector A(3i+2j+5k) to vector B(10i-3j+2k)?


Solve the simultaneous equations x + y = 1 , x^2 -2xy+y^2=9


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences