Solve the simultaneous equations x+2y=4 and x-3y=6

This can be solved in two ways, by substitution or by elimination.Firstly, by substitution, rearrange the first of the two equations in terms of x by subtracting 2y from both sides to get x=4-2y. Then plug that into the second equation. (4-2y) -3y =6 now expand the bracket to get 4 -5y =6. Collect the numbers on the right hand side by subtracting 4 from both sides. -5y = 2 and then divide by -5 to get y = -2/5. Now plug that back into either of the original equations. x +2(-2/5)=4 and expand the bracket. x -4/5=4 and then rearrange the expression to get x= 24/5.This could also by solved by elimination by subtracting the second equation from the first one to eliminate x: 5y=-2. Then divide both sides by 5 to get y=-2/5 and substitute back in as previously described.

Answered by Hamish M. Maths tutor

5568 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Expand the following brackets, (6x^2-4)(2x+3)


Solve the simultaneous equations: 4x+5y=13 and 3x-2y=27


How do I simplify 10/(3 root5)?


Circle with centre C, and points A,B,D and E on the circumference of the circle. BD is the diameter of the circle. Angle CDA is 18 deg and angle AED is 31 deg. Find angle EDA.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences