Integrate y=(x^2)cos(x) with respect to x.

This problem must be solved using integration by parts, since y is equal to the product of two functions of x. Let u=x^2, therefore u'=2x (u'=du/dx). Let v'=cos(x), therefore v=sin(x) (v'=dv/dx).Using the integration by parts formula: Intgrl(y)dx= uv - Intgrl(vu')dx (which is given on the A Level maths formula sheet), Intgrl(y)dx=x^2(sin(x)) - Intgrl(2x(sin(x))dx). We must apply the same rule again, since 2x(sin(x)) cannot be integrated directly. u=2x, u'=2v'=sin(x), v=-cos(x). Intgrl(y)dx=x^2(sin(x)) - [-2x(cos(x)) - intgrl(2(-cos(x))dx], -2cos(x) can now be integrated giving the final solution: Intgrl(y)=x^2(sin(x)) + 2x(cos(x)) - 2(sin(x)) + c.

AH
Answered by Antony H. Maths tutor

3939 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Solve 29cosh x – 3cosh 2x = 38 for x, giving answers in terms of natural logarithms


Differentiate x^cos(x) and find the derivative of cosec^-1(x)


Two points have coordinates (1,-6) and (-2,3). Find the equation of the line which joins them, and their midpoint.


How would I go about finding the coordinates minimum point on the curve eg y = e^(x) - 9x -5?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning