How do I solve simultaneous equations using the substitution method?

2y + x = 8 (equation 1) and 1 + y = 2x (equation 2)Step 1: make y subject of equation 2: y = 2x - 1 Step 2: sub this value of y into equation 1: 2(2x - 1) + x = 8 Step 3: solve the above equation to find x: 4x -2 + x = 8 --> 5x = 10 --> x = 2 Step 4: sub this value of x into either equation 1: 1 + y = 2(2) --> y = 4 - 1 --> y = 3 Answer: x = 2 and y = 3

LH

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equations y= 3x +4 and y= 2x + 5


Calculate the length of the hypotenuse of a right-angled triangle when the other two sides measure 6cm and 9cm.


Solve:


Expand (x+3)(x+6)