How do I solve simultaneous equations using the substitution method?

2y + x = 8 (equation 1) and 1 + y = 2x (equation 2)Step 1: make y subject of equation 2: y = 2x - 1 Step 2: sub this value of y into equation 1: 2(2x - 1) + x = 8 Step 3: solve the above equation to find x: 4x -2 + x = 8 --> 5x = 10 --> x = 2 Step 4: sub this value of x into either equation 1: 1 + y = 2(2) --> y = 4 - 1 --> y = 3 Answer: x = 2 and y = 3

LH
Answered by Lulu H. Maths tutor

2951 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

ln(2x^2 +9x-5) =1+ ln( x^2+2x-15)


Expand and simplify (x+3)(x+5)


How does differentiation work?


Find the value of x: x^2-3x-3=1


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences