How to solve the simultaneous equations: 3x+5y=19 and 4x+6y=22

First find a shared factor between the x's or the y's. Both 5 and 6 are a factor of 30. So 30/5 is 6 therefore we multiply the whole of equation 1 by 6 to get 18x+30y=114. Then 30/6 =5 so we multiply the whole of the second equation by 5 which is 20x+30y=110. Minus the second equation from the first equation (114-110=4, 18x-20x=-2x, 30y-30y=0) gets us -2x=4 (we have eliminated y in order to find x). This gives x-2. We then plug that back into either equation to get 3(-2)+5y=19 therefore 5y=25 so y is 5.

Answered by Rachel K. Maths tutor

2666 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve algebraically the simultaneous equations x^2 + y^2 = 25 and y - 3x = 13


Why does the translation y=f(x+2) translate the graph f(x) 2 units left instead of 2 to the right?


Expand and simplify 3(m+4)-2(4m+1)


How can I solve a quadratic equation by factorisation?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences