How to solve the simultaneous equations: 3x+5y=19 and 4x+6y=22
First find a shared factor between the x's or the y's. Both 5 and 6 are a factor of 30. So 30/5 is 6 therefore we multiply the whole of equation 1 by 6 to get 18x+30y=114. Then 30/6 =5 so we multiply the whole of the second equation by 5 which is 20x+30y=110. Minus the second equation from the first equation (114-110=4, 18x-20x=-2x, 30y-30y=0) gets us -2x=4 (we have eliminated y in order to find x). This gives x-2. We then plug that back into either equation to get 3(-2)+5y=19 therefore 5y=25 so y is 5.
RK
Related Maths GCSE answers
All answers ▸expand and simplify 2(c+5)+5(c-7)
The rectangles A and B have perimeters of 94cm and 56cm as shown below (insert diagram). Rectangle A: base = 2x cm, height = 3y cm. Rectangle B: base = (x+6)cm, height = (y+4)cm. Use an algebraic method to calculate the area of each rectangle. (8 marks)
Simplify the following fraction - Numerator = 2(8-k) + 4(k-1) Denominator = k^2 - 36
Expand (t+5)(t-2)