For all values of x, f(x) = (x + 1)^2 and g(x) = 2(x-1). Show that gf(x) = 2x(x + 2).
f(x)=(x+1)^2g(x)=2(x-1)
gf(x)=2([(x+1^2)]-1) =2([(x+1)(x+1)]-1) =2([x^2+2x+1]-1) =2(x^2+2x) =2x(x+2)
f(x)=(x+1)^2g(x)=2(x-1)
gf(x)=2([(x+1^2)]-1) =2([(x+1)(x+1)]-1) =2([x^2+2x+1]-1) =2(x^2+2x) =2x(x+2)
