Find the exact solution to ln(2y+5) = 2 + ln(4-y)
Solution is y = 4e2 - 5 /2+e2
By applying log laws we can reach the following:
ln(2y+5/4-y) = 2
Given that ln x = log e x :e2 = 2y+5/4-y
Solve linearly :
2y+5 = e2(4-y)
2y+5 = 4e2 - ye2
2y + ye2= 4e2 -5
y(2 + e2) = 4e2 - 5
y = 4e2 - 5 /2+e2
