Find the roots of this equation: y=(8-x)lnx

To find the roots, let y=0 and find the places where the graph crosses the x-axis. When y=0, (8-x)lnx =0. This can be solved by splitting the terms and putting each =0. This is because if the answer is 0, one or both of the two things multiplied together must be equal to 0. Therefore, (8-x)=0 and lnx=0. These solve to give x=8 and x=1.

ES
Answered by Ella S. Maths tutor

5278 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Differentiate y = 2e^(2x+1)


A curve (C) with equation y=3x^(0.5)-x^(1.5) cuts the X axis at point A and the origin, calculate the co-ordinates of point A.


Show that (sec(x))^2 /(sec(x)+1)(sec(x)-1) can be written as (cosec(x))^2.


The graphs of functions f(x)=e^x and h(x)=e^(-.5x), where x is a real number and 0<x<1 ,lie on a plane. Draw these functions and find the area they and the line x=0.6 enclose using integration correct to 3 decimal places


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning