Solve (2x+3)(4x-2)=0

To solve a simulatious equation, you should place the contents of each bracket equal to 0.
so (2x+3)=0 and (4x-2)=0
Lets start with the equation on the left.
2x+3=0
Minus 3 from both sides of the equation leaving you with 2x=-3 Then divide both sides by 2 leaving the equation at x= -3/2 - this is your answer

for the equation on the right (4x-2)=0
4x-2=0
add 2 to both sides (as adding is opposite to minusing) giving you 4x=2 divide both sides by 4 leaving you with the answer x=2/4
(Note: This answer can be further simplified by dividing both the top and the bottom of the fraction by the same number - in this case both the top and the bottom can be divided by 2, leaving the alternate answer as 1/2)

CP
Answered by Catherine P. Maths tutor

4239 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

√(6^2+8^2)=^3√125a^3


Lily is buying theatre tickets. 4 adult tickets at £15 each 2 child tickets at £10 each A 10% booking fee is added to the ticket price. 3% is then added for paying by credit card. Work out the total ticket price if Lily is paying by card?


Solve these simultaneous equations. 2x + y = 18 x - y = 6


The equation of Line 1 is y=2x-2 and the equation of Line 2 is 2y-4x+5=0. Prove that these 2 lines are parallel to each other.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning