A point A lies on the line y = 2x^2 - 8x + 2. A has y-coordinate (-4). Find all possible values for the x-coordinate of A.

The point A = (x', y') lies on the line y = 2x2 - 8x +2. And we are given that y' = -4.Therefore we have that -4 = 2x2 - 8x +2, which simplifies to x2 - 4x + 3 = 0. Solutions for this quadratic equation are 1 and 3.

Answered by Hasnat K. Maths tutor

2397 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

A linear sequence is as follows: a+b, a+3b, a+5b .... The 2nd term is equal to 15. The 6th term is 47. What is the value of a? What is the value of b? Show your working.


The area of square ABCD is 10 cm^2 . Show that x^2 + 6x = 1 (requires diagram which I will draw on the whiteboard).


Find the roots of x^2-9=0


Draw a graph of x = (y + 4)/4


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences