Find the derivative of y=arcsinx
To differentiate we must use implicit differentiation. So: siny=x .Differentiating both sides we get (dy/dx)cosy=1, so (dy/dx)=1/cosy . Using the common identity (sin2(y)+cos2(y)=1) we can rewrite the denominator so we have: (dy/dx)=1/((1-sin2y)(1/2)) we can then substitute sin y with the identity we have in the first line of working: (dy/dx)=1/(1-x2)(1/2)
Related Maths A Level answers
All answers ▸The polynomial f(x) is defined by f(x) = 18x^3 + 3x^2 + 28x + 12. Use the Factor Theorem to show that (3x+2) is a factor of f(x).
Solve for x (where 0<x<360) 2sin^2(x) - sin(x) - 1 = 0
