Make y the subject of the formula x = SQRT((y+1)/(y-2))

Square both sidesMultiply by the RHS denominator (x^2(y-2)) = y+1Expand your brackets y(x^2) - 2x^2 = y + 1Begin re-arranging towards making y the subject so moving y terms to the left would get you y(x^2 - 1) = 2x^2 +1isolate y, making it the subject, by dividing the co-efficient on both sides (div by (x^2 - 1)) y(x^2 - 1) = 2x^2 +1 (div by (x^2 - 1))y = (2x^2 +1)/(x^2 - 1)

YE
Answered by Youness E. Further Mathematics tutor

7481 Views

See similar Further Mathematics GCSE tutors

Related Further Mathematics GCSE answers

All answers ▸

This is a question from a past paper: https://prnt.sc/r6jnxc


express z(2+i)=(1+2i)^2 in the form z=x+iy


The coefficient of the x^3 term in the expansion of (3x + a)^4 is 216. Find the value of a.


Solve the following simultanious equations: zy=28 and 2z-3y=13


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning