Find the coordinates of the stationary points y=x^4-8x^2+3

Begin with the equation: y = x4-8x2+3. Differentiate by bringing the power down and reducing the power by 1 of each of the terms with x in and constant terms (3) become zero. dy/dx = 4x3-16x. Stationary point is at dy/dx = 0. 4x3-16x = 0. Solve like a normal cubic equation, x = 0, x = -2, x = 2. Sub into original equation to get y coordinate. So coordinates of stationary points are (0,3) (-2,13) and (2,13).

Answered by Finlay H. Maths tutor

5562 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

The line AB has equation 3x + 5y = 7. What is the gradient of AB?


FP2 (old specification) - How do you find the derivative of arsinhx?


By first expanding the brackets, differentiate the equation: y=(4x^4 + 3x)(2x^2 - 9)


The curve has the equation y= (x^3)/(2x-1). Find dy/dx.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences