David left his basketball outside overnight. At 1am the volume of air within the ball was 1.2m^3 and the outdoor temperature was 5 degrees Celsius. At 3am the temperature was -7 degrees Celsius. What is the volume of air inside the ball at 3am?

For this question we solve it using Charles’ Law. Charles’ law states that the product of volume and temperature gives a constant value. This is illustrated by VT=C. This means that volume and temperature are inversely proportional to each other. In simpler terms this means that as volume decreases the temperature will increase and vice versa. We can use this to solve questions like the above. It is important to note in questions involving Charles’ law that temperature MUST be in Kelvin instead of degrees Celsius. To convert degrees to kelvin we add 273.V1/T1= V2/T21.2/(5+273)=V2/(-7+273)1.2/278= V2/266V2=(1.2/278) x 266V2=1.148201V2=1.14 m3

Answered by Skye K. Physics tutor

1225 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

Can you explain the different ways heat can travel?


A bowling ball is thrown into the alley, having velocity of 3 ms^-1 at the start of the bowling alley. It decelerates at a constant rate, before hitting the skittles at 2 ms^-1 after 4 s A) calculate the acceleration of the ball.


what force does a person have to exert on one side of a seesaw if the other person weighs 70kg and is the same distance away from the pivot (2m) on the other side of the seesaw?


How do you calculate efficiency?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences