find the equation of the tangent to the curve y=2x^3+3 at the point where x= -2
know to differentiate to find the gradient of the tangent: y=2x3+3, dy/dx= 6x2When x=-2, dy/dx= 24When x=-2, y=2(-2)3+3, y= -13equation of a tangent is y=mx+c, where y=-13, x=-2 and m=24. Evaluate for c: -13=24(-2)+c, -13=-48+c, -13+48=c, c=35equation of the tangent: y=24x+35
DH
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