find the equation of the tangent to the curve y=2x^3+3 at the point where x= -2

know to differentiate to find the gradient of the tangent: y=2x3+3, dy/dx= 6x2When x=-2, dy/dx= 24When x=-2, y=2(-2)3+3, y= -13equation of a tangent is y=mx+c, where y=-13, x=-2 and m=24. Evaluate for c: -13=24(-2)+c, -13=-48+c, -13+48=c, c=35equation of the tangent: y=24x+35

Answered by David H. Maths tutor

4424 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Expand and simplify 3(x-2) -2(x+2)


Solve the simultaneous equations. 2x + y = 18 x - y = 6


Simplify and then solve by factorisation 3x(x+2)-7=2, to find x.


When rolling two dice, what is the probability of rolling 7?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences