Write x^2 + 4x - 16 in the form (x+a)^2-b

Concentrate on the x^2+4x. Halve the 4 or any number that occupies that space. Equals 2 in this case. Put (x+2)^2 and that is your first term. Expand the brackets= x^2 + 4x + 4. Don't want the extra + 4 as that just results from the expansion of brackets, so minus the 4. Go back to the original equation (x^2 + 4x - 16) and there is a -16 on the end. Can put it all together into: (x^2 + 4x + 4) -4 - 16= (x^2 + 4x + 4)- 20. Final answer= (x+2)^2-20.

LB
Answered by Lucy B. Maths tutor

8219 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve 2x+1=11


The equation of line L is y = 3x - 2 and the equation of line Q is 3y - 9x + 5 = 0, show these two lines are parallel


Solve for x : 2x-15=-2x-7


A car costs £1200 in a sale. It was reduced by 20%. What was the original price?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences