A titration is carried out and 0.04dm^3 of sulphuric acid neutralises 0.08dm^3 sodium hydroxide of concentration 1mol/dm^3. Calculate the concentration of the sulphuric acid.

The first thing to do with this titration calculation is write the balanced symbol equation for the reaction. Using the knowlege that when an acid and base react a salt and water is produced we can write:

H2SO4 (aq)+ 2NaOH (aq) ---> Na2SO4 (aq)+ 2H2(l)

From the balanced symbol equation we can see that 1 mole of H2SO4 neutralises 2 moles of NaOH

The next thing to do is calculate the number of moles of sodium hydroxide that were used up in the reaction.

We use the equation: number of moles = concentration x volume

N =    1 mol/dm3   x 0.08dm3 = 0.08 moles of NaOH

The number of moles of H2SO4 used up in the reaction is therefore half of this (0.04 moles) since we established from the symbol equation that 1 mole of H2SO4 neutralises 2 moles of NaOH.

Finally we can calculate the concentration of H2SO4 by using the equation :

concentration = number of moles/ volume

c = 0.04mol/ 0.04dm3 = 1mol/dm3
 

Answered by Victor A. Chemistry tutor

3329 Views

See similar Chemistry GCSE tutors

Related Chemistry GCSE answers

All answers ▸

Why is Chlorine a gas at room temperature but Sodium Chloride is a solid?


What is the electron configuration of Oxygen? Give it in terms of shells and subshells.


What is the difference between ionic and covalent bonding?


Explain why DNA replication is considered semi-conservative.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences