The first thing to do with this titration calculation is write the balanced symbol equation for the reaction. Using the knowlege that when an acid and base react a salt and water is produced we can write:
H2SO4 (aq)+ 2NaOH (aq) ---> Na2SO4 (aq)+ 2H2O (l)
From the balanced symbol equation we can see that 1 mole of H2SO4 neutralises 2 moles of NaOH
The next thing to do is calculate the number of moles of sodium hydroxide that were used up in the reaction.
We use the equation: number of moles = concentration x volume
N = 1 mol/dm3 x 0.08dm3 = 0.08 moles of NaOH
The number of moles of H2SO4 used up in the reaction is therefore half of this (0.04 moles) since we established from the symbol equation that 1 mole of H2SO4 neutralises 2 moles of NaOH.
Finally we can calculate the concentration of H2SO4 by using the equation :
concentration = number of moles/ volume
c = 0.04mol/ 0.04dm3 = 1mol/dm3