Find dy/dx when y=2x^(4)+3x^(-1)
To differentiate this equation we use the power rule. This means that we times the power by the coefficient, this now becomes our new coefficient. Then you subtract 1 from the old power and this becomes your new power. So dy/dx=8x^(3)-3x^(-2).
RC
Related Further Mathematics GCSE answers
All answers ▸A curve has equation y = ax^2 + 3x, when x= -1, the gradient of the curve is -5. Work out the value of a.
Point A lies on the curve: y=x^2+5*x+8. The x-coordinate of A is -4. What is the equation of the normal to the curve at A?
The circle c has equation x^2+ y ^2=1 . The line l has gradient 3 and intercepts the y axis at the point (0, 1). c and l intersect at two points. Find the co-ordinates of these points.
How can a system of two linear equations be solved?