Find dy/dx when y=2x^(4)+3x^(-1)
To differentiate this equation we use the power rule. This means that we times the power by the coefficient, this now becomes our new coefficient. Then you subtract 1 from the old power and this becomes your new power. So dy/dx=8x^(3)-3x^(-2).
RC
Related Further Mathematics GCSE answers
All answers ▸Find and describe the stationary points of the curve y = x^2 + 2x - 8
Find the stationary points of y=x^3 + 3x^2 - 9x - 4
Why does tanx = sinx/cosx ?
x^3 + 2x^2 - 9x - 18 = (x^2 - a^2)(x + b) where a,b are integers. Work out the three linear factors of x^3 + 2x^2 - 9x - 18. (Note: x^3 indicates x cubed and x^2 indicates x squared).