Find dy/dx when y=2x^(4)+3x^(-1)

To differentiate this equation we use the power rule. This means that we times the power by the coefficient, this now becomes our new coefficient. Then you subtract 1 from the old power and this becomes your new power. So dy/dx=8x^(3)-3x^(-2).

Related Further Mathematics GCSE answers

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Find the stationary points of y=x^3 + 3x^2 - 9x - 4


What is differentiation used for?


A curve is mapped by the equation y = 3x^3 + ax^2 + bx, where a is a constant. The value of dy/dx at x = 2 is double that of dy/dx at x = 1. A turning point occurs when x = -1. Find the values of a and b.


The line y = 3x-4 intersects the curve y = x^2 - a, where a is an unknown constant number. Find all possible values of a.


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