For this you’ll want to use the integration by parts method. In this the form u use is:integral of udv = uv - integral of vduTherefore we can rewrite the integral as ln(x)*1 labelling 1 as dv and ln(x) as u. We then integrate 1 and differentiate ln(x) to get x and 1/x respectively. Then we plug this into the formula to get the answer of:xln(x) - integral of x/x (i.e just 1)After the second integration we get the answer to be xln(x) -x + C remembering to not forget the C when we are integrating without bounds.