Solve simultaneously: x^2+y^2=25 and y-3x=13

The substitution method means we have to rearrange the linear equation to find a variable, either x or y, then substitute it into the quadratic (and more difficult to solve) equation, as follows...x2+y2=25 y=3x+13x2+(3x+13)2=25x2+9x2+78x+169=2510x2+78x+144=05x2+39x+72Factorise...(5x+24)(x+3)=0x=-24/5, x=-3Sub in linear equation for y...when x=-24/5, y=-7/5when x=-3, y=4

SC
Answered by Saffron C. Maths tutor

3181 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Express x^2 + 10x – 3 in the form (x + p)^2 + q


How do i solve simultaneous equations?


Prove that the square of an odd number is always 1 more than a multiple of 4


What is 16^(3/2)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning