This is an example of an energy consideration problem involving work done in the context of a Hooke's law situation. Firstly draw a diagram to show what's going on. Then recall that the work done by the air resistance on the jumper = the loss in TOTAL energy of the jumper. Consider first the initial energy, it will have GPE relative to where the length is 5.9m, GPE = mgh = mg(5.9), now at the point where the total length is 5.9m the cord has been extended by 0.9m so it will have Elastic potential AND kinetic energy, = 1/2 kX2 + 1/2 mv2 where k is the stiffness constant and X is the extension (=0.9m) . Remember that work done by the air resistance is = force x distance so = 5.9x4 = 23.6N Formulate these energies as previously discussed i.e. Work done by air resistance = initial GPE - final(EPE + KE) 23.6 = mg(5.9) - 1/2 kX2- 1/2 mv2 where v is the speed at that point and m is the mass(160kg)Rearrange this to make v the subject and substitute the values in for: m, k, X and g = 9.81m/s2 Doing this yields v = 11m/s (given to two significant figures as the minimum number of sig figs given in the question was 2.)