Solve the following simultaneous equations 3x+y=11 and 2x+y=8

To solve a simultaneous equation you should number your equations and re arrange one of them to make y the subject. (You could do it the other way and find the expression for x first)3x + y = 11 [1] and 2x + y = 8 [2]. Re arranging equation [1] we will get the following equation by subtracting 3x from both sides. y = 11 - 3x. Then by substituting the expression for y into equation [2] you can solve for x, giving x = 3. Then we can find the value of y by substituting the value we found for x into equation [1]3(3) + y = 11. 9 +y = 11, giving y =2

Answered by Rachel A. Maths tutor

2399 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

A bag with 750 balls is comprised of 300 red, 200 blue and 250 green. What is the probability of three green balls being in succession, providing the ball is put back between each turn.


Solve the simultaneous equations: y=x^2 + 3x + 7 and y=x + 10


2435 units of gas used in November, costing 4.12p per unit. The gas company also charge 9.43p per day. The total cost has an additional 5% in VAT. What is the gas bill for the month of November?


Solve the Simultaneous equations x^2 + y^2 =29, y-x=3.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences