Solve the simultaneous equations 5x + y = 21 and x - 3y = 9

To begin with, I would begin by explaining that in a situation with simultaneous equations one of the variables must be eliminated to find the values for y and x.In this specific case I would make the x variables have the same coefficient and multiply the second equation by 5 giving 5x-13y=45The next step would be to subtract one equation from the other as so: 5x-13y=45 - 5x + y = 21 resulting in an answer of -16y=24This equation can rearrange to y= -1.5Using this value in either of the original equations you can solve for xBy using x-3y=9 and rearranging for x to give x=9+3y then substituting in the value for y to obtain x=4.5

LO
Answered by Lily O. Maths tutor

2714 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

When do I use a cosine rule over a sine rule?


Write down the coordinates of the turning point of the graph y = x^2 – 8x + 25


Solve the equation: x^2 - 9x + 20 = 0


factorise x^2 - 8x -65


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences