Express f(x) = ln(x+1) as an infinite series in ascending powers of x up to the 3rd power of x

Recall that the Maclaurin series for f(x) is f(x) = f(0) + f'(0)x + f''(0)x²/2! + ... + f^(r)(0)x^r/r! + ... Here f(0) = ln(1+0) = ln1 = 0 , f'(x) = 1/(1+x) using the chain rule. f'(0) = 1/1 = 1 , f''(x) = -1/(1+x)² , f''(0) = -1/(1)² = -1 , f'''(x) = 2/(1+x)³ , f'''(0) = 2/(1)³ = 2, Substituting these into the general expression for the Maclaurin series: (to 3rd degree) gives: ln(1+x) = 0 + 1x + -1/2! x² + 2/3! x³ , ln(1+x) = x - x²/2 + x³/3