Find the tangent to the equation y=x^2 -2x +4 when x=2

When X=2 Y=2^2-2(2)+4=4 So the coordinates are (2,4)Differentiate Y so dy/dx = 2x-2Tangent Gradient when x=2 is 2(2)-2=2 so m=2We need to find the y intercept to get out tangent equationso y=2x+c , we sub in our coordinates to get 4=2(2)+c , c=0So therefore the tangent equation is y=2x

NN
Answered by Nabeel N. Further Mathematics tutor

2012 Views

See similar Further Mathematics GCSE tutors

Related Further Mathematics GCSE answers

All answers ▸

Rationalise and simplify (root(3) - 7)/(root(3) + 1) . Give your answer in the form a + b*root(3) where a, b are integers.


The equation of a curve is y = x^2 - 5x. Work out dy/dx


Work out the equation of the tangent to the curve y=x^2+5x-8 at the point (2,6)


In the expansion of (x-7)(3x**2+kx-3) the coefficient of x**2 is 0. i) Find the value of k ii) Find the coefficient of x. iii) write the fully expanded equation in terms of x


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning