How do you solve two simultaneous equations? (i.e. 5x + y =21 and x - 3y =9)

There are two ways of solving the simultaneous equations. The easiest one is to write two equations beneath each other and then try to get either x or y values the same on both of them by multiplying the value in front of x (or y) on top equation by the whole bottom equation, and the top equation by the coefficient in front of x of bottom equation. In this case we would get 5x + y =21 and 5x - 15y =45. Then at this stage we can subtract the bottom equation from the top one eliminating the x unknown and leaving the equation in terms of y. i.e. y + 15y = 21 - 45 ==> 16 y = -24 ==> y = -3/2. Then we use the calculated value of y to find x by plugging y into one of the two equations. i.e. x -3(-3/2) = 9 ==> x = 9 - 9/2, x = 9/2. Another approach would be to rearrange one equation in terms of x so x = 9 + 3y and then plug it into the other equation and solving that for y. Then follow the same approach.

Answered by Paulina M. Maths tutor

2280 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

What is 3/5 of 65.


Solve algebraically: 6a+3b=24, 3a-b=7


A 20-foot ladder is leaning against a vertical wall. The bottom of the ladder is pulled away horizontally from the wall at 3 feet per second. How fast is the top of the ladder sliding down the wall when the bottom of the ladder is 10 feet away?


y= 6x + 2, Find the gradient of the line and the y-intersect


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences