A=(1,a;0,1/2) B=(1,-1;0,2) AB=I, calculate the value of a.

First notice I is the 2x2 identity matrix (1,0;0,1) now we can form an equation to solve for a, look for an entry where a is involved the (1,2) entry of I is 0 and calculated by 1(-1)+2a=0 now solving gives a=1/2

DS
Answered by Dylan S. Further Mathematics tutor

2191 Views

See similar Further Mathematics GCSE tutors

Related Further Mathematics GCSE answers

All answers ▸

How do you use derivatives to categorise stationary points?


Prove that tan^2(x)=1/(cos^2(x))-1


If y=x^3+9x, find gradient of the tangent at (2,1).


Find dy/dx when y=2x^(4)+3x^(-1)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning