A=(1,a;0,1/2) B=(1,-1;0,2) AB=I, calculate the value of a.

First notice I is the 2x2 identity matrix (1,0;0,1) now we can form an equation to solve for a, look for an entry where a is involved the (1,2) entry of I is 0 and calculated by 1(-1)+2a=0 now solving gives a=1/2

DS
Answered by Dylan S. Further Mathematics tutor

2246 Views

See similar Further Mathematics GCSE tutors

Related Further Mathematics GCSE answers

All answers ▸

Why does the discriminant b^2-4ac determine the number of roots of the quadratic equation ax^2+bx+c=0?


Given a^2 < 4 and a+2b = 8. Work out the range of possible values of b. Give your answer as an inequality.


The coefficient of the x^3 term in the expansion of (3x + a)^4 is 216. Find the value of a.


Consider the Matrix M (below). Find the determiannt of the matrix M by using; (a) cofactor expansion along the first row, (b) cofactor expansion along the second column


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning