A=(1,a;0,1/2) B=(1,-1;0,2) AB=I, calculate the value of a.

First notice I is the 2x2 identity matrix (1,0;0,1) now we can form an equation to solve for a, look for an entry where a is involved the (1,2) entry of I is 0 and calculated by 1(-1)+2a=0 now solving gives a=1/2

Related Further Mathematics GCSE answers

All answers ▸

y=(6x^9 +x^8)/(2x^4), work out the value of d^2y/dx^2 when x=0.5


Given a^2 < 4 and a+2b = 8. Work out the range of possible values of b. Give your answer as an inequality.


write showing all working the following algebraic expression as a single fraction in its simplest form: 4-[(x+3)/ ((x^2 +5x +6)/(x-2))]


Factorise 6x^2 + 7x + 2


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences