A=(1,a;0,1/2) B=(1,-1;0,2) AB=I, calculate the value of a.

First notice I is the 2x2 identity matrix (1,0;0,1) now we can form an equation to solve for a, look for an entry where a is involved the (1,2) entry of I is 0 and calculated by 1(-1)+2a=0 now solving gives a=1/2

Related Further Mathematics GCSE answers

All answers ▸

The line y = 3x-4 intersects the curve y = x^2 - a, where a is an unknown constant number. Find all possible values of a.


The coefficient of the x^3 term in the expansion of (3x + a)^4 is 216. Find the value of a.


3x^3 -2x^2-147x+98=(ax-c)(bx+d)(bx-d). Find a, b, c, d if a, b, c, d are positive integers


How would I solve the following equation d^2x/dt^2 + 5dx/dt + 6x = 0


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences