Assuming no friction, describe the motion of a simple pendulum released from rest at t=0 at amplitude A? Provide information about its speed and position at characteristic times during one period. [The 1D equation of motion is described by a cosine]

The displacement of the bob of mass m is given by the equation x(t)=A cos(w*t), with no phase offset as given by the boundary conditions (zero speed at t=0). By differentiating this equation twice the first and second derivatives of displacement, i.e. speed and acceleration as a function of displacement can be obtained. By finding maxima of these quantities by looking at peaks of higher order derivatives, one can find the times t at which speed and acceleration are maximised and plot the graphs for one period.
Either we can treat this mathematically or provide physical insight into what should happen to the pendulum. As the pendulum is released from rest, the initial speed is zero. Due to the tangential component of the gravitational force, the bob of mass m is accelerated until it reaches a maximum speed at zero height. As the mass continues to move due to inertia and the gravitational force acting now opposite to its motion, it will slow down again and reach the same height as initially (assuming no air resistance etc.).

SA
Answered by Stefan A. Physics tutor

1514 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

Please describe the change in velocity of someone falling from a plane before they open their parachute


What is the difference between speed and velocity?


Calculate the charge that flows past a point in a circuit with a 5.0A current for five minutes.


A bowling ball is thrown into the alley, having velocity of 3 ms^-1 at the start of the bowling alley. It decelerates at a constant rate, before hitting the skittles at 2 ms^-1 after 4 s A) calculate the acceleration of the ball.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences