A class of 10 students all complete a maths exam. Their marks are as follows: 67, 82, 48, 36, 55, 95, 19, 49, 62 and 73. Find the mean, median and range.

First let's start with the mean, the formula for the mean is: (Sum of terms)/(amount of terms). We know the amount of terms is 10 as this is in the questions, to find the sum of the terms we add all the marks (67+82+48+36+55+95+19+49+62+73)=586. Therefore the mean is 586/10= 58.6.To find the median we have to order the numbers smallest to largest: 19,36,48,49,55,62,67,73,82,95. Then choose the N+1/2 term. (10+1)/2 is 5.5th, to find the 5.5th term we take the 5th term and 6th term and average the two i.e (55+62)/2=58.5.The range is the largest minus the smallest i.e 95-19= 76.