The equation of a curve is y=(x+3)^2 +5, what are the co-ordinates of the curve's turning point?

Differentiate y with respect to x:dy/dx = 2(x+3) = 2x+6When the above equation is equal to 0, this is where the turning point of the curve is.2x+6 = 02x = -6x = -3Therefore, at x = -3, the curve has a turning point. To find the y co-ordinate, substitute -3 into the original equation and solve for y:y=(-3+3)^2+5=5Therefore, the co-ordinates of the turning point are (-3,5)

Answered by Harry H. Maths tutor

2880 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve 67x – 5 = 12x + 13


Simultaneous equations - Find the values of y and x: 3


Sam takes out a £720 loan. Sam will have to pay back the £720 plus an interest rate of 15%. He will have to pay this back in 12 equal monthly instalments. How much must Sam pay monthly?


Expand and simplify (x+6)(x-6)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences