3A + 4B =32 6A-2B=14 work out the values of A and B

First we need to get either an equal number of As, an opposite number of As. An equal number of Bs or an opposite number of Bs. 6A-2B= 14 (Multiply by 2) 12A-4B =28 and 3A +4B =32 add together15A=60 (divide by 15) A=4Then substitute A=4 into the original equation3(4) + 4B = 3212 + 4B = 324B=20 (divide by 4)B=5 Then substitue these values into the other equation to see if they work6(4) -2(5) =1424-10 = 1414=14 so does make sense and is correct. A=4 B=5

Answered by Oliver R. Maths tutor

2172 Views

See similar Maths KS3 tutors

Related Maths KS3 answers

All answers ▸

A piece of wire is 240cm long. Peter cuts two 45 cm lengths off the wire. He then cuts the rest of the wire into as many 40cm length as possible. How many wires of 40cm can be cut?


How can I factorise x^2 - 7x + 12?


Solve the equation: 5p − 7 = 3p + 3 .


Differentiate sin^2(x)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences