3A + 4B =32 6A-2B=14 work out the values of A and B

First we need to get either an equal number of As, an opposite number of As. An equal number of Bs or an opposite number of Bs. 6A-2B= 14 (Multiply by 2) 12A-4B =28 and 3A +4B =32 add together15A=60 (divide by 15) A=4Then substitute A=4 into the original equation3(4) + 4B = 3212 + 4B = 324B=20 (divide by 4)B=5 Then substitue these values into the other equation to see if they work6(4) -2(5) =1424-10 = 1414=14 so does make sense and is correct. A=4 B=5

OR
Answered by Oliver R. Maths tutor

2906 Views

See similar Maths KS3 tutors

Related Maths KS3 answers

All answers ▸

Simplify \sqrt{98} - \sqrt{32} giving your answer in the form k*sqrt{2} where k is an integer


Differentiate sin^2(x)


If x=3 and y=7, which of the following gives value of 23?


What is the Pythagoras’ theorem and how can it be used to work out the distance between two points?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning