You are given two equations: 3y-2x=11 and y+x=12. By solving simultaneously, what is the value of x and the value of y.

Begin by setting up the equations simultaneously. To make it easier we can label the equations (1) and (2)3y-2x=11 (1)y+x=12 (2)We then need to make the values of y or the values of x equal in both equations and we can do this through multiplication. So if we make the values of y equal, we need to times equation (2) by 3. Remember to multiply the whole equation by 3.3y-2x=113y+3x=36We can then minus the two equations to cancel out the 3y.-5x=-25Then divide both sides by -5 to give x=5. We then substitute this value back into one of the equations. I am going to substitute it back into equation (2).y+5=12Take away 5 from both sides and y =7Therefore the answer is x=5 and y=7. We can check this answer by substituting the values into equation 1.3(7)-2(5)=11

Answered by Natasha F. Maths tutor

2400 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

The equation of line L1 is y=4x+3, The equation of line L2 is 4y-16x-2=0, Show that these two lines are parallel.


Solve the following quadratic equation x^(2)+7x+12


All tickets for a concert are the same price. Amy and Dan pay £63 altogether for some tickets. Amy pays £24.50 for 7 tickets. How many tickets does Dan buy?


A field is 90m x 45m, next to a circular lake, 20m across. For training, the coach says your team can either run around the lake 3 times or run along 2 sides of the pitch and then back along the diagonal. Which run is the shortest?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences