A car travelling at 28 m/s brakes until it stops completely after travelling a distance of 15 m. Calculate the deceleration of the car.

·        Firstly, we need to note down what we have: distance travelled, s =15 m; initial velocity, u = 28 ms-1; final velocity, v = 0 because the car comes to rest; we are looking for the deceleration hence a; since we are using s, u, v and a, we need to use the "suvat" equation that contains those four letters ----- v2 = u2 + 2as·        By rearranging the equation ---- a = (v2 - u2) / 2s = -282 / (2 x 15) = -784/30 = -26 ms-2 (the minus sign is because deceleration is a decrease in speed rather than an increase)

Answered by Oluyomi S. Physics tutor

2838 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

What is the main evidence for the Big Bang theory?


Describe and explain the vertical motion of a parachutist which jumps out of an aeroplane at time t=0 and then releases the parachute shortly after reaching terminal velocity at time t=T. (Assume air resistance is not negligible).


How am I going to remember all of the particles I need to know? (A-level Physics)


How do I convert between eV and J


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences