The equation of the line L1 is y=4x–8. The equation of the line L2 is 3y–12x+4=0. Show that L1 and L2 are parallel.

Parallel lines have the same gradient. The gradient of L1 is 4. For the gradient of L2: 3y=12x-4y=4x-4/3The gradient of L2 is also 4. Thus these lines are parallel.
Explanation 1.Rearrange the equation to make y the subject: 3y=12x-42.Divide through by 3 to get a single y as the subject: y=4x-4/3

DP
Answered by Divya P. Maths tutor

2990 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Where do the two lines intersect? (a) 3x+6y= 15 (b) y= 6x -4 (GCSE-Higher Tier)


Solve the linear simultaneous equations: 3x + 5y = 45, 2x - 9y = -7


A GCSE is graded out of 140 marks. 1/5 of these marks were given for coursework. The rest were divided between two reading and listening tests, with the marks split in the ratio 3:4 respectively. How many marks were given for the reading test?


What do I need the Pythagoras theorem for?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences