how am I meant to solve sq.root(6^2+8^2) = cube.root(125a^3) when one side is squared and the other is cubed?

first of all, have a look at each side separately to see you you can cancel anything down.e.g. the square and square root can cancel out. => sq.root(6²+8²) = 6+8on the otherside, the cube, and cube root can cancel out => cube.root (125a³) -> cube.root(a³) = a, leaving (cube.root(125))a (is 125 a cube number?)125 is 5³ leaving an equation with no squares, cubes or roots on either sidesq.root(6²+8²) = cube.root(125a³) goes too => 6+8=5a=> 6+8=15 therefore 15=5a=> a=15/5=> a=3